Help with bugs in a C code
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by Yanki Twizzy
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Published on 2010-03-31T14:15:08Z
Indexed on
2010/03/31
14:23 UTC
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c
This C code is giving me some unpredictable results. The program is meant to collect 6 nos and print out the max, position of the max no and the average. It's supposed to have only 3 functions - input, max_avr_pos and output for doing what the code is supposed to do but I am getting unpredictable results. Please what could be the problem
#include <stdio.h>
#include <stdlib.h>
#include <conio.h>
void input_vals(int arrnum[]);
void max_ave_val(int arrnum1[],double *average,int *maxval,int *position);
void print_output(double *average1,int *maxval1,int *position1);
int main(void)
{
int arrnum[6],maxval2,position2;
double average2;
input_vals(arrnum);
max_ave_val(arrnum,&average2,&maxval2,&position2);
print_output(&average2,&maxval2,&position2);
_getche();
return 0;
}
void input_vals(int arrnum[])
{
int count;
printf("\n Please enter six numbers\n");
for(count=0;count<6;count++)
{
scanf("%d",&arrnum[count]);
}
}
void max_ave_val(int arrnum1[],double *average,int *maxval,int *position)
{
int total=0;
int cnt,cnt1,cnt2,limit,maxval2,post;
limit=6;
/* finding the max value*/
for(cnt=0;cnt<limit-1;cnt++)
for(cnt1=limit-1;cnt1>cnt;--cnt1)
{
if(arrnum1[cnt1-1]>arrnum1[cnt1])
{
maxval2=arrnum1[cnt-1];
post=(cnt-1)+1;
}
else
{
maxval2=arrnum1[cnt1];
post=cnt1+1;
}
}
*maxval=maxval2;
*position=post;
/* solving for total */
for(cnt2=0;cnt2<limit;cnt2++);
{
total=total+arrnum1[cnt2];
}
*average=total/limit;
}
void print_output(double *average1,int *maxval1,int *position1)
{
printf("\n value of the highest of the numbers is %d\n",*maxval1);
printf("\n the average of all the numbers is %g\n",*average1);
printf("\n the postion of the highest number in the list is %d\n",*position1);
}
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