Hyphenate a random string to an exact format

Posted by chrissygormley on Stack Overflow See other posts from Stack Overflow or by chrissygormley
Published on 2010-03-31T10:21:44Z Indexed on 2010/03/31 10:33 UTC
Read the original article Hit count: 363

Filed under:
|

Hello,

I am creating a random ID using the below code:

from random import *
import string

# The characters to make up the random password
chars = string.ascii_letters + string.digits

def random_password():

    return "".join(choice(chars) for x in range(32))

This will output something like:

60ff612332b741508bc4432e34ec1d3e

I would like the format to be in this format:

60ff6123-32b7-4150-8bc4-432e34ec1d3e

I was looking at the .split() method but can't see how to do this with a random id, also the hyphen's must be at these places so splitting them by a certain amount of digits is out. I'm asking is there a way to split these random id's by 8 number's then 4 etc.

Thanks

© Stack Overflow or respective owner

Related posts about python

Related posts about string-manipulation