java phone number validation....
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Published on 2010-03-31T17:44:20Z
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2010/03/31
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Here is my problem:
Create a constructor for a telephone number given a string in the form xxx-xxx-xxxx or xxx-xxxx for a local number. Throw an exception if the format is not valid.
So I was thinking to validate it using a regular expression, but I don't know if I'm doing it correctly. Also what kind of exception would I have to throw? Do I need to create my own exception?
public TelephoneNumber(String aString){
if(isPhoneNumberValid(aString)==true){
StringTokenizer tokens = new StringTokenizer("-");
if(tokens.countTokens()==3){
areaCode = Integer.parseInt(tokens.nextToken());
exchangeCode = Integer.parseInt(tokens.nextToken());
number = Integer.parseInt(tokens.nextToken());
}
else if(tokens.countTokens()==2){
exchangeCode = Integer.parseInt(tokens.nextToken());
number = Integer.parseInt(tokens.nextToken());
}
else{
//throw an excemption here
}
}
}
public static boolean isPhoneNumberValid(String phoneNumber){
boolean isValid = false;
//Initialize reg ex for phone number.
String expression = "(\\d{3})(\\[-])(\\d{4})$";
CharSequence inputStr = phoneNumber;
Pattern pattern = Pattern.compile(expression);
Matcher matcher = pattern.matcher(inputStr);
if(matcher.matches()){
isValid = true;
}
return isValid;
}
Hi sorry, yes this is homework. For this assignments the only valid format are xxx-xxx-xxxx and xxx-xxxx, all other formats (xxx)xxx-xxxx or xxxxxxxxxx are invalid in this case.
I would like to know if my regular expression is correct
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