Sort a list of pointers.
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Published on 2010-03-31T15:53:04Z
Indexed on
2010/03/31
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Hello all,
Once again I find myself failing at some really simple task in C++. Sometimes I wish I could de-learn all I know from OO in java, since my problems usually start by thinking like Java.
Anyways, I have a std::list<BaseObject*>
that I want to sort. Let's say that BaseObject
is:
class BaseObject {
protected:
int id;
public:
BaseObject(int i) : id(i) {};
virtual ~BaseObject() {};
};
I can sort the list of pointer to BaseObject
with a comparator struct:
struct Comparator {
bool operator()(const BaseObject* o1, const BaseObject* o2) const {
return o1->id < o2->id;
}
};
And it would look like this:
std::list<BaseObject*> mylist;
mylist.push_back(new BaseObject(1));
mylist.push_back(new BaseObject(2));
// ...
mylist.sort(Comparator());
// intentionally omitted deletes and exception handling
Until here, everything is a-ok. However, I introduced some derived classes:
class Child : public BaseObject {
protected:
int var;
public:
Child(int id1, int n) : BaseObject(id1), var(n) {};
virtual ~Child() {};
};
class GrandChild : public Child {
public:
GrandChild(int id1, int n) : Child(id1,n) {};
virtual ~GrandChild() {};
};
So now I would like to sort following the following rules:
- For any
Child
objectc
andBaseObject
b
,b<c
- To compare
BaseObject
objects, use itsid
s, as before. - To compare
Child
objects, compare itsvar
s. If they are equal, fallback to rule 2. GrandChild
objects should fallback to theChild
behavior (rule 3).
I initially thought that I could probably do some casts in Comparator
. However, this casts away constness. Then I thought that probably I could compare typeid
s, but then everything looked messy and it is not even correct.
How could I implement this sort, still using list<BaseObject*>::sort
?
Thank you
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