How does symbol binding work for shared libraries in linux
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Published on 2010-02-24T16:48:55Z
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2010/04/01
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When compiling a cpp program with g++ -O0 I noticed that my binary does not contain the symbol for the empty string (basic_string): _S_empty_rep_storage When I do compile this same program with -O2 I notice that the aforementioned symbol is indeed contained within the binary as follows (using nm on the bin):
00000000006029a0 V _ZNSs4_Rep20_S_empty_rep_storageE@@GLIBCXX_3.4
My application uses several .so (dynamic libraries) and when my aplication loads I notice that several of these .so files bind as follows (I set LD_DEBUG=all and ran my program):
28596: binding file /home/bbazso/usr/local/lib/mydynamiclib.so [0] to /usr/lib64/libstdc++.so.6 [0]: normal symbol `_ZNSs4_Rep20_S_empty_rep_storageE' [GLIBCXX_3.4]
28596: binding file /home/bbazso/usr/local/lib/mydynamiclib.so [0] to /home/bbazso/workspace/mytestapplication [0]: normal symbol `_ZNSs4_Rep20_S_empty_rep_storageE' [GLIBCXX_3.4]
28596: binding file /home/bbazso/workspace/mytestapplication [0] to /usr/lib64/libstdc++.so.6 [0]: normal symbol `_ZNSs4_Rep20_S_empty_rep_storageE' [GLIBCXX_3.4]**
But I also noticed that one of my .so only binds as follows:
28087: binding file /home/bbazso/usr/local/lib/anotherdynamiclib.so [0] to /usr/lib64/libstdc++.so.6 [0]: normal symbol `_ZNSs4_Rep20_S_empty_rep_storageE' [GLIBCXX_3.4]
but never binds to the binary (mytestapplication) as shown above for the mydynamiclib.so.
So I was wondering what this actually means? Does this mean that anotherdynamiclib.so will use a different symbol for the empty string above than the rest of the application? I guess what I'm really asking is how does symbol binding work in the context of the example above?
Thanks!
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