shell_exec escaping quotes in php for Twitter API

Posted by yc10 on Stack Overflow See other posts from Stack Overflow or by yc10
Published on 2010-04-01T17:51:58Z Indexed on 2010/04/01 17:53 UTC
Read the original article Hit count: 684

Filed under:
|
|
|

I'm (lazily) using shell_exec() to execute a Twitter API Call.

shell_exec('curl -u user:password -d "id=3191321" http://api.twitter.com/1/twitterapi/twitterlist/members.xml');

That works fine when I authenticate correctly and put in a number for the id.

But when I try to put in a variable ($id), it screws up.

$addtolist = shell_exec('curl -u pxlist:Weekend1 -d "id='.$id.'" http://twitter.com/username/twitterlist/members.xml');

I tried flipping the quote types

$addtolist = shell_exec("curl -u pxlist:Weekend1 -d 'id=$id' http://twitter.com/username/twitterlist/members.xml");

I tried using double quotes and escaping them

$addtolist = shell_exec("curl -u pxlist:Weekend1 -d \"id=$id\" http://twitter.com/username/twitterlist/members.xml");

None of them worked.

What am I doing wrong?

© Stack Overflow or respective owner

Related posts about php

Related posts about shell