Having trouble setting up API call using array of parameters

Posted by Josh on Stack Overflow See other posts from Stack Overflow or by Josh
Published on 2010-04-03T01:20:45Z Indexed on 2010/04/03 1:23 UTC
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I am building a class to send API calls to Rapidshare and return the results of said call. Here's how I want the call to be done:

$rs = new rs();

$params = array(
    'sub'   =>  'listfiles_v1',
    'type'  =>  'prem',
    'login' =>  '10347455',
    'password'  =>  'not_real_pass',
    'realfolder'    => '0',
    'fields'    => 'filename,downloads,size',
    );

print_r($rs->apiCall($params));

And here's the class so far:

class RS
{
    var $baseUrl = 'http://api.rapidshare.com/cgi-bin/rsapi.cgi?sub=';

    function apiCall($params)
    {
        $newUrl = $baseUrl;
        $keys = array_keys($params);
        $count = count($params);
        for($i = 0; $i < $count; $i++)
        {
            $newUrl .= $keys[$i];
            $newUrl .= '&';
            $newUrl .= $params[$keys[$i]];
        }
        return $newUrl;
    }
}

Obviously i'm returning $newUrl and using print_r() to test the query string, and this is what it comes out as with the code shown above:

sub&listfiles_v1type&premlogin&10347455password&_not_real_passrealfolder&0fields&filename,downloads,size

When it should be:

http://api.rapidshare.com/cgi-bin/rsapi.cgi?sub=listfiles_v1&type=prem&login=10347455&password=not_real_pass&realfolder=0&fields=filename,downloads,size

Hopefully you can see what I'm trying to do here :P It's probably a silly mistake that I'm failing to find or a logical error.

Thanks in advance.

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