RSA PKCS1 implementation in Python

Posted by user307016 on Stack Overflow See other posts from Stack Overflow or by user307016
Published on 2010-04-03T15:30:36Z Indexed on 2010/04/03 15:33 UTC
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rsa

I'm working on the RSA PKCS1 implementation in Python,here's the message block i got:

m = [0,2,random paddings,0,message integers]

I read the RFC2313,and get a equation seems for transforming the message block object into an big-edian integer. I just get confused about how to transform it in Python.

Any help would be appreciated.

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RSA PKCS1 implementation in Python - Developer IT

RSA PKCS1 implementation in Python

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