php database image show problem
Posted
by Termedi
on Stack Overflow
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or by Termedi
Published on 2010-04-05T07:50:40Z
Indexed on
2010/04/05
7:53 UTC
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Hit count: 223
here is the code
<?php
session_start();
if(!isset($_SESSION['user_name']))
{
header('Location: login.php');
}
$conn = mysql_connect("localhost", "root", "") or die("Can no connect to Database Server");
?>
<html>
<head>
</head>
<body>
<center>
<div id="ser">
<form action="" method="post">
<label for="file">Card No:</label>
<input type="text" name="card_no" id="card_no" class="fil" onKeyUp="CardNoLength()" onKeyDown="CardNoLength()" onKeyPress="CardNoLength()"/>
<input type="submit" name="search" value="Search" class="btn" onClick="return CardNoLengthMIN()"/>
</form>
</div>
</center>
<br/><hr style="border: 1px solid #606060 ;" />
<center><a href="index.php">Home</a></center>
<br/>
<center>
<?php
if(isset($_POST['card_no']))
{
if($conn)
{
if(mysql_select_db("img_mgmt", $conn))
{
$sql = "select * from temp_images where card_no='".trim($_POST['card_no'])."'";
$result = mysql_query($sql);
$image = mysql_fetch_array($result);
if(isset($image['card_no']))
{
//echo "<img src=\"".$image['file_path']."\" alt=\"".$image['card_no']."\" width=\"250\" height=\"280\"/>";
header("Content-type: image/jpeg");
echo $image['img_content'];
}
else
{
echo "<p style=\"color:red;\">Sorry, Your search came with no results ! <br/> Try with different card number";
}
}
else
{
echo "Database selection error: ".mysql_error();
}
}
else
{
echo "Could not connect: ".mysql_error();
}
}
?>
</center>
</body>
</html>
But it after executing the script it shows:
Cannot modify header information - headers already sent by (output started at C:\xampp\htdocs\img\search.php:61) in C:\xampp\htdocs\img\search.php on line 77
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