Pointer Arithmetic & Signed / Unsigned Conversions!

Posted by Jay on Stack Overflow See other posts from Stack Overflow or by Jay
Published on 2010-04-05T12:54:19Z Indexed on 2010/04/05 13:03 UTC
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Incase of pointer arithmetic, are the integers automatically converted to their signed variants? If yes, why?

Suppose I do

pointer + uiVal 

where pointer is a pointer to int and uiVal is initialized to -1, then I find that the address in pointers get decremented by 4. Why is the unsigned value of -1 not considered here?

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