Python list as *args?
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by Cap
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Published on 2010-04-05T21:15:19Z
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2010/04/05
21:33 UTC
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I have two Python functions, both of which take variable arguments in their function definitions. To give a simple example:
def func1(*args):
for arg in args:
print arg
def func2(*args):
return [2 * arg for arg in args]
I'd like to compose them -- as in func1(func2(3, 4, 5))
-- but I don't want args
in func1
to be ([6, 7, 8],)
, I want it to be (6, 7, 8)
, as if it was called as func1(6, 7, 8)
rather than func1([6, 7, 8])
. Normally, I would just use func1(*func2(3, 4, 5))
or have func1
check to see if args[0]
was a list. Unfortunately, I can't use the first solution in this particular instance and to apply the second would require doing such a check in many places (there are a lot of functions in the role of func1
).
Does anybody have an idea how to do this? I imagine some sort of introspection could be used, but I could be wrong.
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