How do I break down an NSTimeInterval into year, months, days, hours, minutes and seconds on iPhone?

Posted by willc2 on Stack Overflow See other posts from Stack Overflow or by willc2
Published on 2009-08-06T09:08:48Z Indexed on 2010/04/06 2:03 UTC
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I have a time interval that spans years and I want all the time components from year down to seconds.

My first thought is to integer divide the time interval by seconds in a year, subtract that from a running total of seconds, divide that by seconds in a month, subtract that from the running total and so on.

That just seems convoluted and I've read that whenever you are doing something that looks convoluted, there is probably a built-in method.

Is there?

I integrated Alex's 2nd method into my code.

It's in a method called by a UIDatePicker in my interface.

NSDate *now = [NSDate date];
NSDate *then = self.datePicker.date;
NSTimeInterval howLong = [now timeIntervalSinceDate:then];

NSDate *date = [NSDate dateWithTimeIntervalSince1970:howLong];
NSString *dateStr = [date description];
const char *dateStrPtr = [dateStr UTF8String];
int year, month, day, hour, minute, sec;

sscanf(dateStrPtr, "%d-%d-%d %d:%d:%d", &year, &month, &day, &hour, &minute, &sec);
year -= 1970;

NSLog(@"%d years\n%d months\n%d days\n%d hours\n%d minutes\n%d seconds", year, month, day, hour, minute, sec);

When I set the date picker to a date 1 year and 1 day in the past, I get:

1 years 1 months 1 days 16 hours 0 minutes 20 seconds

which is 1 month and 16 hours off. If I set the date picker to 1 day in the past, I am off by the same amount.

Update: I have an app that calculates your age in years, given your birthday (set from a UIDatePicker), yet it was often off. This proves there was an inaccuracy, but I can't figure out where it comes from, can you?

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