How do I write this URL in Django?

Posted by alex on Stack Overflow See other posts from Stack Overflow or by alex
Published on 2010-04-06T21:08:05Z Indexed on 2010/04/06 21:13 UTC
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(r'^/(?P<the_param>[a-zA-z0-9_-]+)/$','myproject.myapp.views.myview'),

How can I change this so that "the_param" accepts a URL(encoded) as a parameter?

So, I want to pass a URL to it.

mydomain.com/http%3A//google.com

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