Python: Picking an element without replacement

Posted by wpeters on Stack Overflow See other posts from Stack Overflow or by wpeters
Published on 2010-04-06T18:42:21Z Indexed on 2010/04/06 18:53 UTC
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I would like to slice random letters from a string.

Given s="howdy"

I would like to pick elements from 's' without replacement but keep the index number.

For example

>>> random.sample(s,len(s))
['w', 'h', 'o', 'd', 'y']

is close to what I want, but I would actually prefer something like

[('w',2), ('h',0), ('o',1), ('d',3), ('y',4)]

with letter-index pairs. This is important because the same letter appears in 's' more than once. ie) "letter" where 't' appears twice but I need to distinguish the first 't' from the 'second'.

Ideally I actually only need to pick letters as I need them but scrambling and calculating all the letters in a list (as shown above) is ok.

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