Knight movement.... " how to output all possible moves. "

Posted by josh kant on Stack Overflow See other posts from Stack Overflow or by josh kant
Published on 2010-04-07T19:20:39Z Indexed on 2010/04/07 19:23 UTC
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hi tried the following code and is still not working. it is having problem on backtracking. it just fills the squares of a board with numbers but not in expected order. The code is as follows :

include

include

using namespace std;

int i=0; int permuteno = 0;

bool move(int *p[], int *used[] ,int x, int y,int n, int count); bool knights (int *p[], int *used[],int x,int y,int n, int count); void output(int *p[],int n);

int main(char argc, char *argv[]) { int count = 1; int n; //for size of board int x,y; // starting pos int **p; // to hold no. of combinations int **used; // to keep track of used squares on the board

if ( argc != 5) { cout << "Very few arguments. Please try again."; cout << endl; return 0; }

n = atoi(argv[2]); if( argv[1] <= 0 ) { cout << " Invalid board size. "; return 0; }

x = atoi(argv[4]); y = atoi(argv[4]);

cout << "board size: " << n << ", "<< n << endl; cout << "starting pos: " << x << ", " << y << endl;

//dynamic allocation of arrays to hold permutation p = new int *[n]; for (int i = 0; i < n; i++) p[i] = new int [n];

//dynamic allocation of used arrays used = new int*[n]; for (int i = 0; i < n; i++) used[i] = new int [n];

//initializing board int i, j; for (i=0; i

output(p,n);

if (knights(p,used,x, y, n, count)) { cout << "solution found: " << endl <

int i, j;

for (i=0; i

else { cout << "Solution not found" << endl; output (p, n); }

knights (p,used, x, y, n, 1);

//knights (p,used,x, y, n, count); cout << "no. perm " << permuteno << endl;

return 0; }

void output(int *p[],int n) { int i = 0,j; while ( i !=n) { for ( j=0; j

bool move(int *p[], int *used[] ,int x, int y,int n,int count) {

if (x < 0 || x >= n) { return false; } if ( y < 0 || y >= n) { return false; } if( used[x][y] != 0) { return false; } if( p[x][y] != 0) { return false; }

count++; return true; }

bool knights (int *p[], int *used[], int x,int y,int n ,int count) { //used[x][y] = 1;

if (!move(p,used,x,y,n, count)) { return false; }

if (move(p,used,x,y,n, count)) { i++; }

p[x][y] = count; used[x][y] = 1;

cout << "knight moved " << x << ", " << y << " " << count << endl;

if(n*n == count) { return true; }

//move 1 if (!knights (p,used, x-1, y-2, n, count+1)) { used[x][y] = 0; //p[x][y] = 0; } //move 2 if (!knights (p,used, x+1, y-2, n, count+1)) { used[x][y] = 0; //p[x][y] = 0; } //move 3 if (!knights (p,used, x+2, y-1, n, count+1)) { used[x][y] = 0; //p[x][y] = 0; } //move 4 if (!knights (p,used, x+2, y+1, n, count+1)) { used[x][y] = 0; //p[x][y] = 0; } //move 5 if (!knights (p,used, x+1, y+2, n, count+1)) { used[x][y] = 0; //p[x][y] = 0; } //move 6 if (!knights (p,used, x-1, y+2, n, count+1)) { used[x][y] = 0; //p[x][y] = 0; } //move 7 if (!knights (p,used, x-2, y+1, n, count+1)) { used[x][y] = 0; //p[x][y] = 0; } //move 8 if (!knights (p,used, x-2, y-1, n, count+1)) { used[x][y] = 0; //p[x][y] = 0; } permuteno++; //return true;
//}while ( x*y != n*n );

return false; }

I has to output all the possible combinations of the knight in a nXn board..

any help would be appreciated...

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