I have a simple program to check if a port is open, but I want to shorten the timeout length on the socket connection because the default is far too long. I'm not sure how to do this though. Here's the code:

#include <sys/socket.h>
#include <sys/time.h>
#include <sys/types.h>
#include <arpa/inet.h>
#include <netinet/in.h>
#include <errno.h>
#include <fcntl.h>
#include <stdio.h>
#include <netdb.h>
#include <stdlib.h>
#include <string.h>
#include <unistd.h>

int main(int argc, char **argv) {
    u_short port;                /* user specified port number */
    char addr[1023];             /* will be a copy of the address entered by u */
    struct sockaddr_in address;  /* the libc network address data structure */
    short int sock = -1;         /* file descriptor for the network socket */

    if (argc != 3) {
        fprintf(stderr, "Usage %s <port_num> <address>", argv[0]);
        return EXIT_FAILURE;
    }

    address.sin_addr.s_addr = inet_addr(argv[2]); /* assign the address */
    address.sin_port = htons(atoi(argv[2]));            /* translate int2port num */

    sock = socket(AF_INET, SOCK_STREAM, 0);
    if (connect(sock,(struct sockaddr *)&address,sizeof(address)) == 0) {
        printf("%i is open\n", port);
    }  
    close(sock);
    return 0;
}