How to use a variable in an awk expression

Posted by lugte098 on Stack Overflow See other posts from Stack Overflow or by lugte098
Published on 2010-04-08T10:24:36Z Indexed on 2010/04/08 10:33 UTC
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I'm trying to make this command:

sed bla bla filename | awk '{printf "%s %s_entry_%.3f %.3f %.3f %.3f",$1,$3,$4,$5,$6,$7}'

But the thing is, i want the %.3f part to be variable. So in one case it could be %.3f and in another it could be %.3f %.3f %.3f. So i'll just use a static one in my example code for clarity. So if i want 4 of these %.3f and put them in variable $values like so:

values="%.3f %.3f %.3f %.3f"

Then how can i put this string in the awk expression, without making awk to just put literally "${values}" in there. The following is my non-working-attempt:

sed bla bla filename | awk '{printf "%s %s_entry_${values}",$1,$3,$4,$5,$6,$7}'

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