Filling a byte array in Java
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by Corleone
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Published on 2010-04-10T18:29:55Z
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2010/04/10
18:33 UTC
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Hey all!
For part of a project I'm working on I am implementing a RTPpacket where I have to fill the header array of byte with RTP header fields.
//size of the RTP header:
static int HEADER_SIZE = 12; // bytes
//Fields that compose the RTP header
public int Version; // 2 bits
public int Padding; // 1 bit
public int Extension; // 1 bit
public int CC; // 4 bits
public int Marker; // 1 bit
public int PayloadType; // 7 bits
public int SequenceNumber; // 16 bits
public int TimeStamp; // 32 bits
public int Ssrc; // 32 bits
//Bitstream of the RTP header
public byte[] header = new byte[ HEADER_SIZE ];
This was my approach:
/*
* bits 0-1: Version
* bit 2: Padding
* bit 3: Extension
* bits 4-7: CC
*/
header[0] = new Integer( (Version << 6)|(Padding << 5)|(Extension << 6)|CC ).byteValue();
/*
* bit 0: Marker
* bits 1-7: PayloadType
*/
header[1] = new Integer( (Marker << 7)|PayloadType ).byteValue();
/* SequenceNumber takes 2 bytes = 16 bits */
header[2] = new Integer( SequenceNumber >> 8 ).byteValue();
header[3] = new Integer( SequenceNumber ).byteValue();
/* TimeStamp takes 4 bytes = 32 bits */
for ( int i = 0; i < 4; i++ )
header[7-i] = new Integer( TimeStamp >> (8*i) ).byteValue();
/* Ssrc takes 4 bytes = 32 bits */
for ( int i = 0; i < 4; i++ )
header[11-i] = new Integer( Ssrc >> (8*i) ).byteValue();
Any other, maybe 'better' ways to do this?
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