How to use the Value of a Selected Value from a DropDownList populated with AJAX/PHP
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Published on 2010-04-10T14:01:15Z
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2010/04/10
14:03 UTC
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Hi,
I have form with two dropdownlists (lets say A and B). When I select a value from A, B is being populated accordingly using AJAX
In the same page I have a button, that when pressed, posts the values of the selected items of the dropdownlists to another PHP page. The problem I am having is that the selected value of B is returned as Blank/Empty.
Is there a way to store the selected value of a dropdownlist populated using AJAX?
Code below:
(Main FORM)
<form name="NewBar" method="post" onsubmit="return validateFormOnSubmit(this)" action="AssignContactDetailToBar_f.php">
<tr>
<td width="150"><b>Bar:</b></td>
<td>
<select name = "bar" onChange="getContact('AssignContactDetailToBar_f_getContacts.php?bar='+this.value)" size = 1 style = "width:190px">
<option value = "">---Select---</option>
<?php
while ($data = mysql_fetch_array($r_getBarsDetails))
{
echo "<option value=\"".$data['bar_id']."\">".$data['bar_name']." (".$data['town_name'].")</option>";
}
?>
</td>
</tr>
<tr>
<td width="150"><b>Contact Person:</b></td>
<td>
<div id="persondiv"><select name = "person" size = 1 style = "width:190px">
<option value = "">--Select Bar--</option>
</td>
</tr>
<tr>
<td>
<input name="security" type="text" size="15">
</td>
<td>
<input type="submit" name="Submit" value="Submit">
</td>
</tr>
</form>
FORM to populate the 2nd Dropdownlist
<select name="person" size = 1 style = "width:190px">
<option value = "">--Select Person--</option>
<?php
while($data=mysql_fetch_array($result))
{
echo "<option value=\"".$data['person_id']."\">".$data['person_name']." ".$data['person_surname']." (".$data['town_name'].")</option>";
} ?>
if you would like to see the complete code download from here
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