Get #part in URL with PHP/Symfony

Posted by fesja on Stack Overflow See other posts from Stack Overflow or by fesja
Published on 2010-04-12T17:46:38Z Indexed on 2010/04/12 17:53 UTC
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Hi,

I'm working with Symfony 1.2. I've a view with a list of objects. I can order them, filter them by category, or moving to the next page (there is pagination). Everything is done with AJAX, so I don't have to load all the page again.

What I want to achieve is to have http://urltopage#page=1&order=title&cats=1,2 for example; so the new page is saved in the browser history, and he can paste it to another web.

I haven't found a way to get the #part. I know that's only for the browser but I can't believe I can't get through PHP. I'm sure there is a simple solution I'm missing...

thanks a lot!

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