Call a void* as a function without declaring a function pointer
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Published on 2010-04-14T07:50:22Z
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2010/04/14
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I've searched but couldn't find any results (my terminology may be off) so forgive me if this has been asked before.
I was wondering if there is an easy way to call a void*
as a function in C without first declaring a function pointer and then assigning the function pointer the address;
ie. assuming the function to be called is type void(void)
void *ptr;
ptr = <some address>;
((void*())ptr)(); /* call ptr as function here */
with the above code, I get error C2066: cast to function type is illegal in VC2008
If this is possible, how would the syntax differ for functions with return types and multiple parameters?
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