Python: some newbie questions on sys.stderr and using function as argument

Posted by Cawas on Stack Overflow See other posts from Stack Overflow or by Cawas
Published on 2010-04-14T00:16:35Z Indexed on 2010/04/14 0:23 UTC
Read the original article Hit count: 676

I'm just starting on Python and maybe I'm worrying too much too soon, but anyways...

log = "/tmp/trefnoc.log"

def logThis (text, display=""):
    msg = str(now.strftime("%Y-%m-%d %H:%M")) + " TREfNOC: " + text
    if display != None:
        print msg + display
    logfile = open(log, "a")
    logfile.write(msg + "\n")
    logfile.close()
    return msg

def logThisAndExit (text, display=""):
    msg = logThis(text, display=None)
    sys.exit(msg + display)

That is working, but I don't like how it looks. Is there a better way to write this (maybe with just 1 function) and is there any other thing I should be concerned under exiting?


Now to some background...

Sometimes I will call logThis just to log and display. Other times I want to call it and exit. Initially I was doing this:

logThis ("ERROR. EXITING")
sys.exit()

Then I figured that wouldn't properly set the stderr, thus the current code shown on the top.

My first idea was actually passing "sys.exit" as an argument, and defining just logThis ("ERROR. EXITING", call=sys.exit) defined as following (showing just the relevant differenced part):

def logThis (text, display="", call=print):
    msg = str(now.strftime("%Y-%m-%d %H:%M")) + " TREfNOC: " + text
    call msg + display

But that obviously didn't work. I think Python doesn't store functions inside variables. I couldn't (quickly) find anywhere if Python can have variables taking functions or not! Maybe using an eval function? I really always try to avoid them, tho. Sure I thought of using if instead of another def, but that wouldn't be any better or worst.

Anyway, any thoughts?

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