Has anyone found the need to declare the return parameter of a copy assignment operator const?
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by Keith
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Published on 2010-04-15T21:20:43Z
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2010/04/15
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c++
|assignment-operator
The copy assignment operator has the usual signature:
my_class & operator = (my_class const & rhs);
Does the following signature have any practical use?
my_class const & operator = (my_class const & rhs);
You can only define one or the other, but not both.
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