As i understand, if we declare a variable as volatile, then it will not be stored in the local cache. Whenever thread are updating the values, it is updated to the main memory. So, other threads can access the updated value.

But in the following program both volatile and non-volatile variables are displaying same value.

The volatile variable is not updated for the second thread. Can anybody plz explain this why testValue is not changed.

class ExampleThread extends Thread {
    private int testValue1;
    private volatile int testValue;
    public ExampleThread(String str){
      super(str);
    }
    public void run() {
    if (getName().equals("Thread 1 "))
    {
        testValue = 10;
        testValue1= 10;
        System.out.println( "Thread 1 testValue1 : " + testValue1);
        System.out.println( "Thread 1 testValue : " + testValue);
    }
    if (getName().equals("Thread 2 "))
    {
        System.out.println( "Thread 2 testValue1 : " + testValue1);
        System.out.println( "Thread 2 testValue : " + testValue);
    }               
}
}

public class VolatileExample {
    public static void main(String args[]) {
        new ExampleThread("Thread 1 ").start();
        new ExampleThread("Thread 2 ").start();
    }
}

output:
Thread 1 testValue1 : 10
Thread 1 testValue : 10
Thread 2 testValue1 : 0
Thread 2 testValue : 0