Php 5 and mysql connecting gives error ...code and error in there check out and plz..plz help....

Posted by user309381 on Stack Overflow See other posts from Stack Overflow or by user309381
Published on 2010-04-16T11:31:43Z Indexed on 2010/04/16 11:33 UTC
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**mysql_query() [function.mysql-query]: Access denied for user 'SYSTEM'@'localhost' (using password: NO) in C:\wamp\www\photo_gallery\includes\database.php on line 56

Warning: mysql_query() [function.mysql-query]: A link to the server could not be established in C:\wamp\www\photo_gallery\includes\database.php on line 56

The Query has problemAccess denied for user 'SYSTEM'@'localhost' (using password: NO) i have set the password for root and grant privilege all for root.Why it soes show like SYSTEM@localhost i dont have SYSTEM .**

class MySQLDatabase { public $connection; function _construct() { $this->open_connection(); } public function open_connection() { /* $DB_SERVER = "localhost"; $DB_USER = "root"; $DB_PASS = ""; $DB_NAME = "photo_gallery";*/ $this->connection = mysql_connect($DBSERVER,$DBUSER,$DBPASS); if(!$this->connection) { die("Database Connection Failed" . mysql_error()); } else { $db_select = mysql_select_db($DBNAME,$this->connection); if(!$db_select) { die("Database Selection Failed" . mysql_error()); } } } function mysql_prep($value) { if (get_magic_quotes_gpc()) { $value = stripslashes($value); } // Quote if not a number if (!is_numeric($value)) { $value = "'" . mysql_real_escape_string($value) . "'"; } return $value;

}
public function close_connection()
{
    if(isset($this->connection))
    {
        mysql_close($this->connection);
        unset($this->connection);
    }
}
public function query($sql)
{
    //$sql = "SELECT*FROM users where id = 1";
    $result = mysql_query($sql);
    $this->confirm_query($result);

    //$found_user = mysql_fetch_assoc($result);
    //echo $found_user;
    return $found_user;
}
private function confirm_query($result)
{
    if(!$result)
    {
        die("The Query has problem" . mysql_error());
    }
}

}

$database = new MySQLDatabase();

?>

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