Python: How to get the caller's method name in the called method?
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Published on 2010-04-16T15:18:59Z
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2010/04/16
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Python: How to get the caller's method name in the called method?
Assume I have 2 methods:
def method1(self):
...
a = A.method2()
def method2(self):
...
If I don't want to do any change for method1, how to get the name of the caller (in this example, the name is method1) in method2?
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