currently i create xmppservlet like below

public void doPost(HttpServletRequest req, HttpServletResponse resp)
                        throws IOException {

                JID jid = new JID("[email protected]");
                Message msg = new MessageBuilder()
                    .withRecipientJids(jid)
                    .withBody("hi Hello i'm a fancy GAE app, how are you?")
                    .build();
                XMPPService xmpp = XMPPServiceFactory.getXMPPService();

                   SendResponse status = xmpp.sendMessage(msg);

}

by doing this, from [email protected], i need to send a message to [email protected] only, will [email protected] send out the message back to [email protected]. Is there anyway to programatically send out xmpp message without having [email protected] to initial chat window with [email protected] and send the first message? This should be consider outbound-service right?

how to do this?