How do I get the position of a result in the list after an order_by?

Posted by Bob Bob on Stack Overflow See other posts from Stack Overflow or by Bob Bob
Published on 2010-04-17T17:09:34Z Indexed on 2010/04/17 17:13 UTC
Read the original article Hit count: 310

Filed under:
|
|
|
|

I'm trying to find an efficient way to find the rank of an object in the database related to it's score. My naive solution looks like this:

rank = 0
for q in Model.objects.all().order_by('score'):
  if q.name == 'searching_for_this'
    return rank
  rank += 1

It should be possible to get the database to do the filtering, using order_by:

Model.objects.all().order_by('score').filter(name='searching_for_this')

But there doesn't seem to be a way to retrieve the index for the order_by step after the filter.

Is there a better way to do this? (Using python/django and/or raw SQL.)

My next thought is to pre-compute ranks on insert but that seems messy.

© Stack Overflow or respective owner

Related posts about django

Related posts about python