Why is there ambiguity in this diamond pattern?
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by cambr
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Published on 2010-04-17T13:48:44Z
Indexed on
2010/04/17
14:03 UTC
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Hit count: 438
Filed under:
c++
|diamond-problem
#include <iostream>
using namespace std;
class A { public: void eat(){ cout<<"A";} };
class B: public A { public: void eat(){ cout<<"B";} };
class C: public A { public: void eat(){ cout<<"C";} };
class D: public B,C { public: void eat(){ cout<<"D";} };
int main(){
A *a = new D();
a->eat();
}
I am not sure this is called diamond problem or not, but why doesn't this work?
When I said, a->eat() (remember eat() is not virtual), there is only one possible eat() to call, that of A.
Why then, do I get this error:
'A' is an ambiguous base of 'D'
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