c - why does it make sense that indexing a character pointer is an int?
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Published on 2010-04-18T10:13:36Z
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char *a = "apple";
printf("%s\n", a); \\ fine
printf("%s\n", a[1]); \\ compiler complains an int is being passed
Why does indexing a string pointer give me an int? I was expecting it to just print the string starting at position one (which is actually what happens when i use &a[1]
instead). why do i need to get the address?
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