how to use xsl:param value in the xsl:attribute name="width"

Posted by Elena on Stack Overflow See other posts from Stack Overflow or by Elena
Published on 2010-04-18T21:16:40Z Indexed on 2010/04/18 21:23 UTC
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It sounds easy, but none of my "easy" syntax worked: xsl:param="length" xsl:attribute name="width">$length not xsl:attribute name="width"> any suggestions?

thanks

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