Multiple sendto() using UDP socket
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Published on 2010-04-18T12:39:13Z
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2010/04/18
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Hi,
I have a network software which uses UDP to communicate with other instances of the same program. For different reasons, I must use UDP here.
I recently had problems sending huge ammounts of data over UDP and had to implement a fragmentation system to split my messages into small data chunks. So far, it worked well but I now encounter an issue when I have to send a lot of data chunks.
I have the following algorithm:
- Split message into small data chunks (around 1500 bytes)
- Iterate over the data chunks list and for each, send it using
sendto()
However, when I send a lot of data chunks, the receiver only gets the first 6 messages. Sometimes it misses the sixth and receives the seventh. It depends.
Anyway, sendto()
always indicates success. This always happen when I test my software over a loopback interface (127.0.0.1) but never over my LAN network.
If I add something like std::cout << "test" << std::endl;
between the sendto()
then every frame is received.
I am aware that UDP allows packet loss and that my frames might be loss for a lot of reasons and I suppose it has to do with the rate I am sending the data chunks at.
What would be the right approach here ?
- Implementing some acknowledgement mechanism (just like TCP) seems overkill.
- Adding some arbitrary waiting time between the
sendto()
is ugly and will probably decrease performance. - Increasing (if possible) the receiver UDP internal buffer ? I don't even know if this is possible.
- Something else ?
I really need your advices here.
Thank very much.
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