How to get address of va_arg?
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by lionbest
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Published on 2010-04-19T21:00:56Z
Indexed on
2010/04/19
21:03 UTC
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I hack some old C API and i got a compile error with the following code:
void OP_Exec( OP* op , ... )
{
int i;
va_list vl;
va_start(vl,op);
for( i = 0; i < op->param_count; ++i )
{
switch( op->param_type[i] )
{
case OP_PCHAR:
op->param_buffer[i] = va_arg(vl,char*); // ok it works
break;
case OP_INT:
op->param_buffer[i] = &va_arg(vl,int); // error here
break;
// ... more here
}
}
op->pexec(op);
va_end(vl);
}
The error with gcc version 4.4.1 (Ubuntu 4.4.1-4ubuntu9)
was:
main.c|55|error: lvalue required as unary ‘&’ operand
So why exactly it's not possible here to get a pointer to argument?
How to fix it? This code is executed very often with different OP*
, so i prefer to not allocate extra memory.
Is it possible to iterate over va_list knowing only the size of arguments?
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