Report viewer in wpf and selection formula
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by shabi
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Published on 2010-01-01T07:25:19Z
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2010/04/19
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I have a WPF application that I would like to present SQL Server Reporting Services sql 2008 reports in. I understand we have to use host widow control and then in report viewer control. I want to use remote processing mode. My code sample is : I have added namespaces:
using System.Windows.Forms;
using System.Windows.Forms.Integration;
using Microsoft.Reporting;
using Microsoft.ReportingServices;
using Microsoft.Reporting.WinForms;
My XAML:
xmlns:wfi="clr-namespace:System.Windows.Forms.Integration;assembly=WindowsFormsIntegration"
xmlns:wf="clr-namespace:System.Windows.Forms;assembly=System.Windows.Forms"
xmlns:wfr="clr-namespace:Microsoft.Reporting.WinForms;assembly=Microsoft.ReportViewer.WinForms"
Title="ReportHost" Height="300" Width="300">
<Grid>
<wfi:WindowsFormsHost Height="100" Margin="39,27,39,0" Name="winFormsHost" VerticalAlignment="Top" >
<wfr:ReportViewer x:Name="rptViewer" ProcessingMode="Remote" />
</wfi:WindowsFormsHost>
</Grid>
Code: rptViewer.ServerReport.ReportServerUrl = new Uri("http://mymachine-:8080/ReportServer_myreports"); rptViewer.ServerReport.ReportPath="/Reports/mytestreport.rdl"; rptViewer.ServerReport.Refresh();
My question is that how how can I set selection formula in microsoft report viewer control [like crystal report]. Or miscroft provided any this else which behave like selection formula in crystal reports.
And when I run the code it show only report viewer in host window control but not the report data in window.
Please some one provide me all step list, Which I have to fallow to get required result with sample code.
Quick response will be appricated.
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