Python urllib.urlopen IOError
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by Michael
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Published on 2010-04-20T03:19:20Z
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2010/04/20
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So I have the following lines of code in a function
sock = urllib.urlopen(url)
html = sock.read()
sock.close()
and they work fine when I call the function by hand. However, when I call the function in a loop (using the same urls as earlier) I get the following error:
> Traceback (most recent call last):
File "./headlines.py", line 256, in <module>
main(argv[1:])
File "./headlines.py", line 37, in main
write_articles(headline, output_folder + "articles_" + term +"/")
File "./headlines.py", line 232, in write_articles
print get_blogs(headline, 5)
File "/Users/michaelnussbaum08/Documents/College/Sophmore_Year/Quarter_2/Innovation/Headlines/_code/get_content.py", line 41, in get_blogs
sock = urllib.urlopen(url)
File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/urllib.py", line 87, in urlopen
return opener.open(url)
File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/urllib.py", line 203, in open
return getattr(self, name)(url)
File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/urllib.py", line 314, in open_http
if not host: raise IOError, ('http error', 'no host given')
IOError: [Errno http error] no host given
Any ideas?
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