xsl literal with <xsl:if>
Posted
by Elena
on Stack Overflow
See other posts from Stack Overflow
or by Elena
Published on 2010-04-20T14:40:30Z
Indexed on
2010/04/20
14:43 UTC
Read the original article
Hit count: 1146
Hi, I have to write a very simple code in xsl: IF column=0 if result = .34 set background color to green and write $result, but if result = 0.10 set background color to white and write the word "QQQ" and what doesn't work is:
<xsl:if test="$result = 0.35 and $column = 0">
<xsl:attribute name='background-color'>#669933</xsl:attribute>
<xsl:value-of select="result"/>
</xsl:if>
<xsl:if test="$result = 0.10">
<xsl:value-of select="QQQ"/>
</xsl:if>
any suggestions? thanks in advance
© Stack Overflow or respective owner