I have a bash shell script that loops through all child directories (but not files) of a certain directory. The problem is that some of the directory names contain spaces.

Here are the contents of my test directory:

$ls -F test
Baltimore/  Cherry Hill/  Edison/  New York City/  Philadelphia/  cities.txt

And the code that loops through the directories:

for f in `find test/* -type d`; do
  echo $f
done

Here's the output:

test/Baltimore
test/Cherry
Hill
test/Edison 
test/New
York
City
test/Philadelphia

Cherry Hill and New York City are treated as 2 or 3 separate entries.

I tried quoting the filenames, like so:

for f in `find test/* -type d | sed -e 's/^/\"/' | sed -e 's/$/\"/'`; do
  echo $f
done

but to no avail.

There's got to be a simple way to do this. Any ideas?

The answers below are great. But to make this more complicated - I don't always want to use the directories listed in my test directory. Sometimes I want to pass in the directory names as command-line parameters instead.

I took Charles' suggestion of setting the IFS and came up with the following:

dirlist="${@}"
(
  [[ -z "$dirlist" ]] && dirlist=`find test -mindepth 1 -type d` && IFS=$'\n'
  for d in $dirlist; do
    echo $d
  done
)

and this works just fine unless there are spaces in the command line arguments (even if those arguments are quoted). For example, calling the script like this: test.sh "Cherry Hill" "New York City" produces the following output:

Cherry
Hill
New
York
City

Again, I know there must be a way to do this - I just don't know what it is...