Image jQuery scroller in a container. (like facebook cropper) can't get values of position.
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by Stefan
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Published on 2010-04-21T20:32:16Z
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2010/04/21
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Hey all.
Having a reallllll mind pain.
I have a php image uploader which is all good and sotring the file and the jquery ajax is returning the image in an ammended html div with a div set up like this:
#crop-holder {
width:80px;
height:80px;
margin:10px 10px 20px 10px;
border:1px #c0c0c0 solid;
overflow:hidden;
cursor:move;
}
The image is viewing fine and I am using the jquery scrollview plugin: http://code.google.com/p/jquery-scrollview/
I have tried adding a few lines to the plugin to store variables of scrollTop and Left and then replacing two hidden input values with x and y in my page. And then on the returned ajax html in the div I am trying to on a button click (for example) retrieve the values of the two hidden inputs....
Heres what i added to the plugin (i'm no js expert!):
.mouseout(function(){
var _m = this.m;
var lasty = _m.scrollTop();
getElementById("ycord").value = lasty;
var lastx = _m.scrollLeft();
getElementById("xcord").value = lastx;
self.stopgrab();
})
Still no luck!!
How can I get the scrollTop and scrollLeft and successfully prepare them for sending onto another php script!?
Thanks:)
stefpretty
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