jQuery monitoring form field created by AJAX query
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by Jon Rhoades
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Published on 2010-04-21T00:17:10Z
Indexed on
2010/04/21
0:23 UTC
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Preface: I am sure this is incredibly simple, but I have searched this site & the jQuery site and can't figure out the right search term to get an answer - please excuse my ignorance!
I am adding additional form fields using jQuery's ajax function and need to then apply additional ajax functions to those fields but can't seem to get jQuery to monitor these on the fly form fields.
How can I get jQuery to use these new fields?
$(document).ready(function() {
$('#formField').hide();
$('.lnk').click(function() {
var t = this.id;
$('#formField').show(400);
$('#form').load('loader.php?val=' + t);
});
//This works fine if the field is already present
var name = $('#name');
var email = $('#email');
$('#uid').keyup(function () {
var t = this;
if (this.value != this.lastValue) {
if (this.timer) clearTimeout(this.timer);
this.timer = setTimeout(function () {
$.ajax({
url: 'loader.php',
data: 'action=getUser&uid=' + t.value,
type: 'get',
success: function (j) {
va = j.split("|");
displayname = va[1];
mail = va[2];
name.val(displayname);
email.val(mail);
}
});
}, 200);
this.lastValue = this.value;
}
});
});
So if the is present in the basic html page the function works, but if it arrives by the $.load function it doesn't - presumably because $(document).ready has already started.
I did try:
$(document).ready(function() {
$('#formField').hide();
$('.lnk').click(function() {
var t = this.id;
$('#formField').show(400);
$('#form').load('loader.php?val=' + t);
prepUid();
});
});
function prepUid(){
var name = $('#name');
var email = $('#email');
$('#uid').keyup(function () {
snip...........
But it didn't seem to work...
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