how do I make a portable isnan/isinf function.
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Published on 2010-02-12T01:40:30Z
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2010/04/23
4:33 UTC
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I've been using isinf,isnan functions on linux platforms which worked perfectly. But this didn't work on osx, so I decided to use std::isinf std::isnan which works on both linux and osx.
But the intel compiler doesn't recognize it, and I guess its a bug in the intel compiler according to http://software.intel.com/en-us/forums/showthread.php?t=64188
So now I just want to avoid the hassle and define my own isinf,isnan implementation.
Does anyone know how this could be done
Thanks
edit: I ended up doing this in my sourcecode for making isinf/isnan working
#include <iostream>
#include <cmath>
#ifdef __INTEL_COMPILER
#include <mathimf.h>
#endif
int isnan_local(double x) {
#ifdef __INTEL_COMPILER
return isnan(x);
#else
return std::isnan(x);
#endif
}
int isinf_local(double x) {
#ifdef __INTEL_COMPILER
return isinf(x);
#else
return std::isinf(x);
#endif
}
int myChk(double a){
std::cerr<<"val is: "<<a <<"\t";
if(isnan_local(a))
std::cerr<<"program says isnan";
if(isinf_local(a))
std::cerr<<"program says isinf";
std::cerr<<"\n";
return 0;
}
int main(){
double a = 0;
myChk(a);
myChk(log(a));
myChk(-log(a));
myChk(0/log(a));
myChk(log(a)/log(a));
return 0;
}
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