Hello,

This question refers to the question http://stackoverflow.com/questions/835259/jquery-show-hide-fields-depening-on-select-value

<select id="viewSelector">
   <option value="0">-- Select a View --</option>       
   <option value="view1">view1</option>
   <option value="view2">view2</option>
   <option value="view3">view3</option>
</select>

<div id="view1">
  <!-- content --> 
</div>
<div id="view2a">
  <!-- content --> 
</div>
<div id="view2b">
  <!-- content --> 
</div>
<div id="view3">
  <!-- content --> 
</div>



$(document).ready(function() {
  $.viewMap = {
    '0' : $([]),
    'view1' : $('#view1'),
    'view2' : $('#view2a, #view2b'),
    'view3' : $('#view3')
  };

  $('#viewSelector').change(function() {
    // hide all
    $.each($.viewMap, function() { this.hide(); });
    // show current
    $.viewMap[$(this).val()].show();
  });
});

When I select the 2nd item in the menu it shows the corresponding field.

The exception to this is when the on page load the select menu already has the 2nd menu item selected, the field does not show.

As you may be able to tell, I am new to jquery and could definetly use some help with adjusting this code so that the selected item's field is shown on page load.

Thanks,

Tim