How do I compute a variable in Javascript if and only if it is used?
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by LLer
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Published on 2010-04-24T05:13:47Z
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2010/04/24
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JavaScript
|variables
This is what I'm doing right now.
var foo = function() {
var x = someComplicatedComputationThatMayTakeMoreTime();
this.foo = function() { return x; };
return x;
}
It works but only if foo is called as a function like so
foo();
But what if I want to call it as a normal variable with a value? I could modify the code to be
var foo = function() {
var x = someComplicatedComputationThatMayTakeMoreTime();
this.foo = x;
return x;
}
That would allow me to only call it once as a function and after that as a regular variable. But it's still not what I want. Plus it gets complicated if it accidentally gets called as a function again, returning an error.
Is this even possible in Javascript?
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