using .append to build a complex menu
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by gneandr
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Published on 2010-04-26T12:36:27Z
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2010/04/26
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To build a menu block which should be switchable with hide/unhide of the menu items, I'm using .append html. The code idea is this:
navigat += '<h3 class="infoH3"> <a id="' + menuID +'"'
+ ' href="javascript:slideMenu(\'' + menuSlider + '\');">'
+ menuName + '</a></h3>';
navigat += '<div id="' + menuSlider + '" style="display:none">';
navigat += ' <ul>';
navigat += ' <li>aMenu1</li>'
navigat += ' <li>aMenu2</li>'
navigat += ' <li>aMenu3</li>'
navigat += ' </ul>';
navigat += '<!-- menuName Slider --></div>';
$("#someElement").append (navigat);
This is doing well .. so far.
But the point is:: I use JS to read the required menu items (eg. 'aMenu1' together with title and/or link info) from a file to build all that, eg. for 'aMenu1' a complex is composed and $("#someElement").append(someString) is used to add that the 'someElement'.
At the moment I build those html elements line by line. Also OK .. as far as the resulting string has the opening and closing tag, eg. "<li>aMenu2</li>"
.
As can be seen from above posted code there is a line "<div id="' + menuSlider + '" style="display:none">"
.
Appending that -- AFAIS -- the .append is automatically (????) adding "</div>
" which closes the statement.
That breaks my idea of the whole concept! The menu part isn't included in the 'menuSlider '.
QQ: How to change it -- NOT to have that "</div
" added to it??
Günter
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