Can I get an XPathNodeIterator directly from an XPath?
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by Val
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Published on 2010-04-28T03:09:59Z
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I hope I'm just missing something obvious. I have a number of repeating nodes in an XML document:
<root>
<parent>
<child/>
<child/>
</parent>
</root>
I need to examine the contents of each of the <child>
elements in turn, so I need an XPathNodeIterator containing the nodeset of all the <child>
nodes.
If I have an XPath that would select the child nodes, e.g. /root/parent/child
, is there any way to feed that directly to a new XPathNodeIterator? Everything I see in the docs and examples indicates I have to first get an XPathNavigator to the <parent>
, then Select
the child nodes, like:
XPathNavigator nav = datasource.CreateNavigator().SelectSingleNode( "/root/parent" );
XPathNodeIterator it = nav.Select( "./child" );
foreach ( child in it ) { /* do something */ }
I was hoping to skip the XPathNavigator, and intialize the XPathNodeIterator with XPath to the child nodes directly, something like:
XpathNodeIterator it = new XpathNodeIterator("/root/parent/child");
foreach ( child in it ) { /* do something */ }
Possible? The benefit is not only saving a line of code, but I can use a single XPath expression, rather than splitting the path to the <child>
nodes in two, first to get the parent element, then to select its children.
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