Covariance and Contravariance type inference in C# 4.0
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Published on 2010-04-28T21:55:05Z
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2010/04/28
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When we define our interfaces in C# 4.0, we are allowed to mark each of the generic parameters as in
or out
. If we try to set a generic parameter as out and that'd lead to a problem, the compiler raises an error, not allowing us to do that.
Question:
If the compiler has ways of inferring what are valid uses for both covariance
(out
) and contravariance
(in
), why do we have to mark interfaces as such? Wouldn't it be enough to just let us define the interfaces as we always did, and when we tried to use them in our client code, raise an error if we tried to use them in an un-safe way?
Example:
interface MyInterface<out T> {
T abracadabra();
}
//works OK
interface MyInterface2<in T> {
T abracadabra();
}
//compiler raises an error.
//This makes me think that the compiler is cappable
//of understanding what situations might generate
//run-time problems and then prohibits them.
Also,
isn't it what Java does in the same situation? From what I recall, you just do something like
IMyInterface<? extends whatever> myInterface; //covariance
IMyInterface<? super whatever> myInterface2; //contravariance
Or am I mixing things?
Thanks
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