How to find N Consecutive records in a table using SQL
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Published on 2010-04-27T23:17:41Z
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2010/04/28
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Hi, I have the following Table definition with sample data. In the following table, Customer Product & Date are key fields
Table One
Customer Product Date SALE
X A 01/01/2010 YES
X A 02/01/2010 YES
X A 03/01/2010 NO
X A 04/01/2010 NO
X A 05/01/2010 YES
X A 06/01/2010 NO
X A 07/01/2010 NO
X A 08/01/2010 NO
X A 09/01/2010 YES
X A 10/01/2010 YES
X A 11/01/2010 NO
X A 12/01/2010 YES
In the above table, I need to find the N or > N consecutive records where there was no sale, Sale value was 'NO' For example, if N is 2, the the result set would return the following
Customer Product Date SALE
X A 03/01/2010 NO
X A 04/01/2010 NO
X A 06/01/2010 NO
X A 07/01/2010 NO
X A 08/01/2010 NO
Can someone help me with a SQL query to get the desired results. I am using SQL Server 2005. I started playing using ROW_NUMBER() AND PARTITION clauses but no luck. Thanks for any help
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