Interview Q: sorting an almost sorted array (elements misplaced by no more than k)
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Published on 2010-04-28T04:21:04Z
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I was asked this interview question recently:
You're given an array that is almost sorted, in that each of the
N
elements may be misplaced by no more thank
positions from the correct sorted order. Find a space-and-time efficient algorithm to sort the array.
I have an O(N log k)
solution as follows.
Let's denote arr[0..n)
to mean the elements of the array from index 0
(inclusive) to N
(exclusive).
- Sort
arr[0..2k)
- Now we know that
arr[0..k)
are in their final sorted positions... - ...but
arr[k..2k)
may still be misplaced byk
!
- Now we know that
- Sort
arr[k..3k)
- Now we know that
arr[k..2k)
are in their final sorted positions... - ...but
arr[2k..3k)
may still be misplaced byk
- Now we know that
- Sort
arr[2k..4k)
- ....
- Until you sort
arr[ik..N)
, then you're done!- This final step may be cheaper than the other steps when you have less than
2k
elements left
- This final step may be cheaper than the other steps when you have less than
In each step, you sort at most 2k
elements in O(k log k)
, putting at least k
elements in their final sorted positions at the end of each step. There are O(N/k)
steps, so the overall complexity is O(N log k)
.
My questions are:
- Is
O(N log k)
optimal? Can this be improved upon? - Can you do this without (partially) re-sorting the same elements?
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