PHP - REGEX - use string for pattern but exclude it from being removed!

Posted by aSeptik on Stack Overflow See other posts from Stack Overflow or by aSeptik
Published on 2010-04-28T14:44:47Z Indexed on 2010/04/28 14:53 UTC
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php

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regex

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preg-replace

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lookbehind

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lookahead

Hi All guys!

i'm pretty new on regex, i have learned something by the way, but is still pour knowledge!

so i want ask you for clarification on how it work!

assuming i have the following strings, as you can see they can be formatted little different way one from another but they are very similar!

DTSTART;TZID="America/Chicago":20030819T000000
DTEND;TZID="America/Chicago":20030819T010000
DTSTART;TZID=US/Pacific
DTSTART;VALUE=DATE

now i want replace everything between the first A-Z block and the colon so for example i would keep

DTSTART:20030819T000000
DTEND:20030819T010000
DTSTART
DTSTART

so on my very noobs knowledge i have worked out this shitty regex! :-(

preg_replace( '/^[A-Z](?!;[A-Z]=[\w\W]+):$/m' , '' , $data );

but why i'm sure this regex will not work!? :-)

Pls help me!

PS: the title of question is pretty explaned, i want also know how for example use a well know string block for match another...

preg_replace( '/^[DTSTART](?!;[A-Z]=[\w\W]+):$/m' , '' , $data );

..without delete DTSTART

Thanks for the time!

Regards Luca Filosofi

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