Hi all

i'm trying to make a simple GUI with QT 4.6. i made a separete class that represents the menu bar:

MenuBar::MenuBar()
{
    aboutAct = new QAction(tr("&About QT"), this);
    aboutAct->setStatusTip(tr("Show the application's About box"));
    connect(aboutAct, SIGNAL(triggered()), this, SLOT(about()));

    quitAct = new QAction(tr("&Quit"),this);
    quitAct->setStatusTip(tr("Exit to the program"));
    //connect(quitAct, SIGNAL(triggered()), &QApp, SLOT(quit()));

    menuFile = new QMenu("File");
    menuFile->addAction(quitAct);

    menuLinks = new QMenu("Links");

    menuAbout = new QMenu("Info");
    menuAbout->addAction(aboutAct);


    addMenu(menuFile);
    addMenu(menuLinks);
    addMenu(menuAbout);
}

i can't connect the signal of the quitAct with the quit slot of the main application probably because it is not visible from the MenuBar class..

//connect(quitAct, SIGNAL(triggered()), &QApp, SLOT(quit()));

how can i do it?