mysql to excel exporting data using php getting html code also

Posted by pmms on Stack Overflow See other posts from Stack Overflow or by pmms
Published on 2010-04-30T13:45:51Z Indexed on 2010/04/30 13:47 UTC
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hi all following is code for getting xlsheet from mysql using php `

if( ($_POST['Submit']=='generateexcel')) { $tblname=$_GET['generateexcel'];

global $obj_mysql;

$table="tbl_js_login"; // this is the tablename that you want to export to csv from mysql.

function exportMysqlToCsv($table,$filename = 'export.csv') { $csv_terminated = "\n"; $csv_separator = ","; $csv_enclosed = '"'; $csv_escaped = "\"; $sql_query = "select fld_id, fld_fname,fld_lname from $table";

// Gets the data from the database
$result = mysql_query($sql_query);
$fields_cnt = mysql_num_fields($result);


$schema_insert = '';

for ($i = 0; $i < $fields_cnt; $i++)
{
    $l = $csv_enclosed . str_replace($csv_enclosed, $csv_escaped . $csv_enclosed,
        stripslashes(mysql_field_name($result, $i))) . $csv_enclosed;
    $schema_insert .= $l;
    $schema_insert .= $csv_separator;
} // end for

$out = trim(substr($schema_insert, 0, -1));
$out .= $csv_terminated;

// Format the data
while ($row = mysql_fetch_array($result))
{
    $schema_insert = '';
    for ($j = 0; $j < $fields_cnt; $j++)
    {
        if ($row[$j] == '0' || $row[$j] != '')
        {

            if ($csv_enclosed == '')
            {
                $schema_insert .= $row[$j];
            } else
            {
                $schema_insert .= $csv_enclosed . 
 str_replace($csv_enclosed, $csv_escaped . $csv_enclosed, $row[$j]) . $csv_enclosed;
            }
        } else
        {
            $schema_insert .= '';
        }

        if ($j < $fields_cnt - 1)
        {
            $schema_insert .= $csv_separator;
        }
    } // end for

    $out .= $schema_insert;
    $out .= $csv_terminated;

$out1 = strip_tags($out); } // end while

header("Cache-Control: must-revalidate, post-check=0, pre-check=0");
header("Content-Length: " . strlen($out1));
// Output to browser with appropriate mime type, you choose ;)
header("Content-type: text/x-csv");
//header("Content-type: text/csv");
//header("Content-type: application/csv");
header("Content-Disposition: attachment; filename=$filename");
echo $out1;
exit;

}

exportMysqlToCsv($table);

 }

include_once $path."includes/jobseeker_form.php";

/* function is_duplicate($login_name) { global $obj_mysql; $sql="SELECT * FROM tbl_admin_details WHERE fld_login ='$login_name'"; $num=$obj_mysql->get_num_rows($sql); if($num==0) return false; else return true; }*/

?>`

the above code we are using for genrating the xlsheet along with xlsheet we are getting html at th top . following is the screen shot of xlsheetalt text

please provide some help how to remove the html code from xlsheet

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